Join Date: 03 December 2016

Posts: 483

Posted on 03 December 2016 - 04:02 AM

Check it out.

https://relationary.files.wordpress.com/2009/09/einstein.png

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Unsighted Members

Join Date: 18 April 2015

Posts: 2741

Posted on 03 December 2016 - 06:16 AM

nice name

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WavyGelato Members

Join Date: 16 November 2016

Posts: 242

Posted on 03 December 2016 - 10:43 AM

Twinkle twinkle little star, circumference equals 2 pi r.
Nice job on this equation.

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*deleted-191881 Members

Join Date: 01 January 1970

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Posted on 03 December 2016 - 02:50 PM

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Emogan Members

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Posted on 03 December 2016 - 03:16 PM

Well said

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MeMyselfAndCube Members

Join Date: 03 June 2016

Posts: 6161

Last edited on 03 December 2016 - 08:28 PM by MeMyselfAndCube

Hi, @RegalRat.

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SuperNeil64 Members

Join Date: 01 August 2016

Posts: 1698

Posted on 03 December 2016 - 08:29 PM

MeMyselfAndCube wrote

Hi, @RegalRat.

You smart son of a gun.

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*deleted-96553 Members

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Posted on 04 December 2016 - 06:55 PM

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LockedLogic Members

Join Date: 08 May 2016

Posts: 47

Posted on 04 December 2016 - 07:37 PM

Ok so first you divide αβ from both sides getting G=(8πGT)/c^4

Then you divide G from both sides: 1=(8πt)/c^4

Multiplying c^4 to both sides, we get: c^4=8πt

Taking the fourth root of both sides: c=2πt

We all know 2πr is circumference so: c=c

Your equation are right :D

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AlbertEinstein Members

Join Date: 03 December 2016

Posts: 483

Posted on 04 December 2016 - 07:38 PM

LockedLogic wrote

Ok so first you divide αβ from both sides getting G=(8πGT)/c^4

Then you divide G from both sides: 1=(8πt)/c^4

Multiplying c^4 to both sides, we get: c^4=8πt

Taking the fourth root of both sides: c=2πt

We all know 2πr is circumference so: c=c

Your equation are right :D

Thank you for your assistance!

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