Posted on 08 November 2015 - 11:10 AM
Hello. My name is Logan, and I am a friend of SteqlthSniper. I am contacting you solely for this purpose - Steqlth wants to talk to you (Archy) privately. He has a few questions to ask. He friend requested you on Skype and wants to know if you would accept, or follow him on Twitter, or something, so that he can message you a few things. Thanks for reading, and please respond to this thread with your answer/decision, or how you will contact Steqlth. @ArchybotPosted on 08 November 2015 - 11:23 AM
you'll find that on archys profile there is a button that says "send a private message"Posted on 08 November 2015 - 11:31 AM
Qymbaut wrote
Posted on 08 November 2015 - 11:37 AM
TheRealSportsFan wrote
Qymbaut wrote...
Now was that necessary
Posted on 08 November 2015 - 12:27 PM
LogBot4 wrote
TheRealSportsFan wrote...
Now was that necessary
Yes it was, because he tagged archy when that just waste his time, when he could of just pm'd him
Posted on 08 November 2015 - 04:27 PM
iCantRod wrote
LogBot4 wrote...
Yes it was, because he tagged archy when that just waste his time, when he could of just pm'd him
Hes talking about SportsFan quoting Aym when he already said it. It was a pointless post.
Posted on 08 November 2015 - 04:48 PM
Qymbaut wrote
Can we give @Aymbaut a tag for Best Forumer?
Posted on 08 November 2015 - 04:49 PM
OnlyAura wrote
i approve
Posted on 08 November 2015 - 04:52 PM
SkellyBot wrote
iCantRod wrote...
Hes talking about SportsFan quoting Aym when he already said it. It was a pointless post.
Thank you.
Posted on 08 November 2015 - 05:06 PM
There is a PM feature.Posted on 08 November 2015 - 05:07 PM
ItsTene wrote
why
Posted on 08 November 2015 - 06:16 PM
Qymbaut wrote
OnlyAura wrote...
i approve
I need one too
Posted on 08 November 2015 - 06:20 PM
ItsTene wrote
Just to annoy QymBaut
Posted on 08 November 2015 - 08:37 PM
Archy will most likely not accept his skype request, although he may PM him on the website, there's not many other ways he can contact him besides that, sorry.