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HalP!!!
Hello all you math geniuses, I have a question for you all!


2,11,23,31,41,53,61,71,83,_ Fill in the blank

There is a pattern and I can't find it help!!!

EDIT: It's 97
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always love a good challenge, will post again if/when I figure it out
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I believe it is 91
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redpandaarcher wrote

I believe it is 91


that seems too simple though

If you are going purely by patterns, the first integer should be 1
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redpandaarcher wrote

I believe it is 91


Explain?
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Don't think so because all the other numbers are primed and 91 is not prime
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SuperSubh3561 wrote

redpandaarcher wrote...



Explain?

Edit: I get it but as Aymbaut mentioned the first number would have been 1 or 0
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bkweoaiqam
doesn't really translate to anything either
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I am honestly stumped.
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91 is all I can come up with
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Pokenick wrote

91 is all I can come up with

I'll look in to this tomorrow, just to tired today
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not relevant anymore
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Morsinius is g0d, I completely fucked up
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f(n)=a*n^8+b*n^7+c*n^6+d*n^5+e*n^4+f*n^3+g*n^2+h*n+i

f(1) = 2
f(2) = 11
f(3) = 23
f(4) = 31
f(5) = 41
f(6) = 53
f(7) = 61
f(8) = 71
f(9) = 83

Therefore :
(1^8)*a+(1^7)*b+(1^6)*c+(1^5)*d+(1^4)*e+(1^3)*f+(1^2)*g+(1^1)h+i = 2
(2^8)*a+(2^7)*b+(2^6)*c+(2^5)*d+(2^4)*e+(2^3)*f+(2^2)*g+(2^1)h+i = 11
(3^8)*a+(3^7)*b+(3^6)*c+(3^5)*d+(3^4)*e+(3^3)*f+(3^2)*g+(3^1)h+i = 23
(4^8)*a+(4^7)*b+(4^6)*c+(4^5)*d+(4^4)*e+(4^3)*f+(4^2)*g+(4^1)h+i = 31
(5^8)*a+(5^7)*b+(5^6)*c+(5^5)*d+(5^4)*e+(5^3)*f+(5^2)*g+(5^1)h+i = 41
(6^8)*a+(6^7)*b+(6^6)*c+(6^5)*d+(6^4)*e+(6^3)*f+(6^2)*g+(6^1)h+i = 53
(7^8)*a+(7^7)*b+(7^6)*c+(7^5)*d+(7^4)*e+(7^3)*f+(7^2)*g+(7^1)h+i = 61
(8^8)*a+(8^7)*b+(8^6)*c+(8^5)*d+(8^4)*e+(8^3)*f+(8^2)*g+(8^1)h+i = 71
(9^8)*a+(9^7)*b+(9^6)*c+(9^5)*d+(9^4)*e+(9^3)*f+(9^2)*g+(9^1)h+i = 83

Matrix equation should be A^-1B = X

Plug this into wolfram —
(inv(({1^8,1^7,1^6,1^5,1^4,1^3,1^2,1^1,1^0},{2^8,2^7,2^6,2^5,2^4,2^3,2^2,2^1,2^0},{3^8,3^7,3^6,3^5,3^4,3^3,3^2,3^1,3^0},{4^8,4^7,4^6,4^5,4^4,4^3,4^2,4^1,4^0},{5^8,5^7,5^6,5^5,5^4,5^3,5^2,5^1,5^0},{6^8,6^7,6^6,6^5,6^4,6^3,6^2,6^1,6^0},{7^8,7^7,7^6,7^5,7^4,7^3,7^2,7^1,7^0},{8^8,8^7,8^6,8^5,8^4,8^3,8^2,8^1,8^0},{9^8,9^7,9^6,9^5,9^4,9^3,9^2,9^1,9^0}))).({2},{11},{23},{31},{41},{53},{61},{71},{83})

Wolfram didn't work, tried someplace else and got
{{-37679/32094720},{48217/1146240},{-1396249/2292480},{521407/114624},{-84507113/4584960},{43798333/1146240},{-26863629/891520},{4509/6368},{6101/796}}

a = -37679/32094720
b = 48217/1146240
c = -1396249/2292480
d = 521407/114624
e = -84507113/4584960
f = 43798333/1146240
g = -26863629/891520
h = 4509/6368
i = 6101/796

Back to original equation
f(n)=a*n^8+b*n^7+c*n^6+d*n^5+e*n^4+f*n^3+g*n^2+h*n+i

Final equation:
f(n)=(-37679/32094720)*n^8+(48217/1146240)*n^7+(-1396249/2292480)*n^6+(521407/114624)*n^5+(-84507113/4584960)*n^4+(43798333/1146240)*n^3+(-26863629/891520)*n^2+(4509/6368)*n+(6101/796)

Solving for #10:
x = (-37679/32094720)*10^8+(48217/1146240)*10^7+(-1396249/2292480)*10^6+(521407/114624)*10^5+(-84507113/4584960)*10^4+(43798333/1146240)*10^3+(-26863629/891520)*10^2+(4509/6368)*10+(6101/796)
x = -15139/796
x ≈ -19.01

If you think I'm pulling your leg, try substituting n for any of the numbers above.

edit:
This can't be 91 because the pattern wouldn't start if 2 if so– it'd have to be 1 if you followed the pattern below
1 + 10 <– can't be 2 because it breaks the pattern
11 + 12
23 + 8
31 + 10
41 + 12
53 + 8
61 + 10
71 + 12
83 + 8
91
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Read below
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-snip- *Idiotic Answer*
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Apparently it's 97 thanks for your help @Morsinius @WhatDefinesYou @Pokenick @Aymbaut @redpandaarcher
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And @lmBlitz
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Just ask Huahwi he would know
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OMG I WAS RIGHT



I SAID 97 AT FIRST



HAHHAHAHAHHAHA
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